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6 September, 23:30

Of all the numbers whose difference is 36 , find the two that have the minimum product

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  1. 6 September, 23:53
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    54,18

    Step-by-step explanation:

    Let one of the numbers be x. The other number be represented as 36-x

    (x - (36-x) = 36

    open brackets

    x - 36 + x = 36

    x + x = 36 + 36 = 72

    2x = 72

    x = 72/2 = 36

    x = 36

    The product can then be represented as y = x (36-x) or y=36x-x²

    The maximum or minimum is always on the axis of symmetry which has the formula x=-b/2a.

    In our case, the axis of symmetry is - 36/-2, so x=18.

    If one number is 18 and the 2 numbers differentiate by 36, the other number is 18 + 36 = 54

    So the 2 numbers are 18 and 54 and the minimum product is 972
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