Two dressmakers, Sue and Anne, sewed costumes for a local theater production. Sue sewing alone for 10 hours sewed some of the costumes, Anne sewing for 16 hours finished sewing the remaining costumes. How any hours would it have taken Sue alone to sew all of the costumes?

(1) Sue sewed 1 costume every 2 hours.

(2) Sue sewed twice as many costumes working in 10 hours as Anne produced in 16 hours.

Question

Reyna Cisneros

Mathematics

1 April, 12:36

Two dressmakers, Sue and Anne, sewed costumes for a local theater production. Sue sewing alone for 10 hours sewed some of the costumes, Anne sewing for 16 hours finished sewing the remaining costumes. How any hours would it have taken Sue alone to sew all of the costumes?

(1) Sue sewed 1 costume every 2 hours.

(2) Sue sewed twice as many costumes working in 10 hours as Anne produced in 16 hours.

+2

Answers (1)

Know the Answer?

Clinton Bridges · Answer 1

Sue would have taken 15 hours to sew all the costumes.

Step-by-step explanation:

In 10 hours, Sue sewed 5 costumes (1 every 2 hours).

Sue = 5 costumes

Sue sewed in 10 hours, twice as many costumes as Anne in 16 hours. Then 5 is twice costumes than Anne produced. Therefore, Anne sewed 2.5 costumes.

Anne: 2.5 costumes

In total they had to sew 5+2.5 = 7.5 costumes. Then Sue would have taken 7.5*2 = 15 hours to sew them all.