What is the solution to - 4x+5y=14 and 7x+3y=-1

I need the answer now.

X = - 1 and y=2

Proof:

-4x+5y=14 (equation 1)

7x+3y = - 1 (equation 2)

3y = - 7x - 1

y = - 7/3x - 1/3 (equation 3)

(3) into (1)

-4x+5 (-7/3x-1/3) = 14

-4x-35/3x-5/3=14

-47/3x-5/3=14

-47/3x=47/3

x = (-47/3) / (47/3)

x = - 1

sub x = - 1 into (3)

y = - 7/3 (-1) - 1/3

y = 2

One way to solve is to try to cancel out some terms

we till try to cancel out the y terms

-4x+5y=14

7x+3y=-1

find lcm of 3 and 5 the lcm=15

-4x+5y=14

multily by 3

-12x+15y=42

7x+3y=-1

multiply both sides by - 5

-35x-15y=5

add 2 equations together

-12x-35x+15x-15x=42+5

add like terms

-47x=47

divide both sides by 47

-x=1

multpiply by - 1

x=-1

subsitute - 1 for x in one quation

7x+3y=-1

x=-1

7 (-1) + 3y=-1

-7+3y=-1

add 7 to both sides

3y=6

divide both sides by 3

y=2

x=-1

y=2