What are the roots of the polynomial equation x^3-6x = 3x^2-8? Use a graphing calculator and a system of equations.

-40, - 4, 5

-5, 4, 40

-4, - 1, 2

-2, 1, 4

Given the polynomial equation x^3 - 6x = 3x^2 - 8. Which can be simplified into (x^3) - 3 (x^2) - 6x + 8 = 0. The roots of the given equation are x = - 2, x = 1 and x = 4. The order of equation also represents the number of roots of the equation given. Since the highest exponent is 3, there also 3 roots. So the answer is D. 2 - 2, 1, 4

x^3 - 6x = 3x^2 - 8

x^3 - 3x^2 - 6x = - 8

x^3 - 3x^2 - 6x + 8 = 0

now factor:

(x-4) (x^2+x-2) = 0

(x-4) (x-1) (x+2) = 0

the roots are 4, 1, - 2

answer is the last one