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Coleman
Mathematics
31 October, 18:07
How do you solve 3log_3 4a=3?
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Keaton Arias
31 October, 18:30
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3 log₃ 4a=3
1) a (log_b c) = log_b c^a
log₃ (4a) ³=3
2) log_a x=n ⇔ a^n=x
log₃ (4a) ³=3 ⇔ 3³ = (4a) ³
27=64a³
a³=27/64
a=∛ (27/64)
a=3/4
Answer: a=3/4
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