The work of a student to solve the equation 3 (3y - 8) = 10 + 3y is shown below: Step 1: 3 (3y - 8) = 10 + 3y Step 2: 6y - 5 = 10 + 3y Step 3: 3y - 5 = 10 Step 4: 3y = 15 Step 5: y = 5 In which step did the student first make an error and what is the correct step?

Question

Serena Carey

Mathematics

10 October, 06:37

The work of a student to solve the equation 3 (3y - 8) = 10 + 3y is shown below: Step 1: 3 (3y - 8) = 10 + 3y Step 2: 6y - 5 = 10 + 3y Step 3: 3y - 5 = 10 Step 4: 3y = 15 Step 5: y = 5 In which step did the student first make an error and what is the correct step?

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Deanna Cain · Answer 1

Their error is in step 2. They added three to each number in (3y+8) instead of distributing it with multiplication. The correct step would be 9y-24=10y+3