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29 March, 12:36

Which equation is the inverse of y = 16x^2 + 1?

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  1. 29 March, 12:57
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    Switch y and x: x = 16y^2 + 1

    Solve for y: x-1=16y^2

    16y = + - √ (x-1)

    y = + - √ (x-1) / 16
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