The length of a rectangle is five times its width.

If the area of the rectangle is 405 in^2, find its perimeter.

Question

Malone

Mathematics

26 March, 01:33

The length of a rectangle is five times its width.

If the area of the rectangle is 405 in^2, find its perimeter.

+5

Answers (1)

Know the Answer?

Mike Lamb · Answer 1

The answer to your question is: Perimeter = 108 in

Step-by-step explanation:

Data

Length (l) = 5 width (w)

A = 405 in²

Perimeter = ?

Formula

Area = l x w

Perimeter = 2w + 2l

Process

405 = 5w x w

405 = 5w²

405/5 = w²

w = √81

w = 9 in

l = 5 (9) = 45 in

Perimeter = 2 (9) + 2 (45)

= 18 + 90

= 108 in

The length of a rectangle is five times its width.If the area of the rectangle is 405 in^2, find its perimeter.

The length of a rectangle is five times its width.

If the area of the rectangle is 405 in^2, find its perimeter.