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5 January, 02:31

For the function f (x) = x^{2} + 4x - 32 solve the following.

f (x) = 0

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  1. 5 January, 02:35
    0
    x=-8 x=4

    Step-by-step explanation:

    x^2 + 4x - 32

    We want to set this equal to zero

    x^{2} + 4x - 32 = 0

    Factor this equation

    what two numbers multiply together to equal - 32 and add together to equal4

    8 * - 4 = - 32

    8 + - 4 = 4

    (x+8) (x-4) = 0

    Using the zero product property

    x+8 = 0 x-4 = 0

    x+8-8=0-8 x-4+4=0+4

    x=-8 x=4
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