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11 January, 15:17

What is the 6th term of the geometric sequence where a1 = - 4,096 and a4 = 64?

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  1. 11 January, 15:34
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    First, we need to solve for the common ratio from the data given by using the equation.

    a (n) = a (1) r^ (n-1)

    64 = - 4096r^ (4-1)

    64 = - 4096r^3

    r = - 1/4

    Then, we can find the 6th term as follows:

    an = - 4096 r^ (6-1)

    an = - 4096 (-1/4) ^5

    an = 4
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