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Imani
Mathematics
17 January, 11:27
Can you Solve. 3x^2+10x+3
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Keira Conrad
17 January, 11:46
0
You cannot solve for x but you can factor
to solve in ax^2+bx+c form you must find
b=x+y
a times c=x times y
so solve
3 times 3=9
what 2 number multily to get 9 and add to get 10
9=x times y
the numbers are 9 and 1 so
3x^2+1x+9x+3
(3x^2+1x) + (9x+3)
factor
(x) (3x+1) + (3) (3x+1)
reverse distribute
ab+ac=a (b+c)
(x) (3x+1) + (3) (3x+1) = (x+3) (3x+1)
factored out form is (x+3) (3x+1)
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Lexie Beltran
17 January, 11:55
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Simplifying
3x^2 + 10x + 3
Reorder the terms
3 + 10x + 3x^2
Factor a trinomial
(3 + x) (1 + 3x)
Final result
(3 + x) (1 + 3x)
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