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19 September, 19:18

How do you integrate 7xe^-5x²?

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  1. 19 September, 19:42
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    Making assumptions about where parentheses should be,

    Let u = - 7x

    du = - 7dx

    dv = e^ (2x) dx

    v = e^ (2x) / 2

    ∫ - 7xe^ (2x) dx =

    -7xe^ (2x) / 2 - ∫ e^ (2x) / 2 (-7) dx =

    -7xe^ (2x) / 2 + 7e^ (2x) / 4 + c
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