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Draven Mays
Mathematics
19 September, 19:18
How do you integrate 7xe^-5x²?
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Juan Bass
19 September, 19:42
0
Making assumptions about where parentheses should be,
Let u = - 7x
du = - 7dx
dv = e^ (2x) dx
v = e^ (2x) / 2
∫ - 7xe^ (2x) dx =
-7xe^ (2x) / 2 - ∫ e^ (2x) / 2 (-7) dx =
-7xe^ (2x) / 2 + 7e^ (2x) / 4 + c
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