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13 August, 01:40

Three out of seven students in the cafeteria line are chosen to answer survey questions. How many different combinations of three students are possible? 7 C 3 = StartFraction 7 factorial Over (7 minus 3) factorial 3 factorial 7 35 70 210

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Answers (2)
  1. 13 August, 01:47
    0
    The number of different combinations of three students that are possible is 35.

    Step-by-step explanation:

    Given that three out of seven students in the cafeteria line are chosen to answer a survey question.

    The number of different combinations of three students that are possible is given as:

    7C3 (read as 7 Combination 3)

    xCy (x Combination y) is defines as

    x! / (x-y) ! y!

    Where x! is read as x - factorial or factorial-x, and is defined as

    x (x-1) (x-2) (x-3) ... 2*1.

    Now,

    7C3 = 7! / (7 - 3) !3!

    = 7!/4!3!

    = (7*6*5*4*3*2*1) / (4*3*2*1) (3*2*1)

    = (7*6*5) / (3*2*1)

    = 7*5

    = 35

    Therefore, the number of different combinations of three students that are possible is 35.
  2. 13 August, 01:49
    0
    35

    Step-by-step explanation:

    i took the quiz on edg
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