The length of rectangle is 2 yd longer than its width. The perimeter of the rectangle is 32 yd, find its area

The length of a rectangle is 2yd longer than it's width. If the permitter is 32yd find it's area.

Let width be x

Length = x+2 yards

Perimeter = 2 * (l+w)

= 2 * (x+2+x)

=2 * (2x+2)

=4x+4

4x+4 = 32

4x=32-4

4x=28

x=7 = width

length = 9