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6 June, 21:47

A driver intends to complete 2 laps on a track that is exactly 1 mile around at an average speed of 60 mph. He gets off to a slow start and completes the 1st lap at an average of 30 mph. How fast must he drive the second lap in order to achieve his goal?

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  1. 6 June, 21:58
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    Goal is not achievable

    Step-by-step explanation:

    There are Two laps and the total distance here is 2miles. Now, it is said that he hopes to travel at a speed of 60mph, thus the total time that it would take him to complete the 2 miles distance race is 2/60 = 1/30 hours. Thus if he travels at a constant speed of 60mph he would finish the race at 1/30hours.

    This means he will take a time of 1/60 hours per lap.

    Now, he travels 30mph to complete 1 mile, the time taken for this is 1/30h

    We now need to know the speed he travels on the second lap.

    Average speed = Total distance/Total time

    60mph = 2 / (1/30 + T2)

    60 = 2 / ((1 + 30T2) / 30)

    60 = 2 divided by (1 + 30T2) / 30

    60 = 2 * (30) / 1 + 30T2

    60 (1 + 30T2) = 60

    1 + 30T2 = 1

    30T2 = 0

    T2 = 0

    This means that he cannot achieve his goal again as he had taken the time meant for the whole race in a single lap.
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