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30 October, 02:19

If 4 sec a _ 5 = 0, evaluate 2 cos a + 5 sin a : 2 sin a + 5 cos a

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Answers (2)
  1. 30 October, 02:42
    0
    23/26 = 0.8846=0.88 [ to the nearest hundredth]

    Step-by-step explanation:

    4 sec a-5 = 0; seca=1/cos a

    Therefore;

    4 sec a-5 = 0=>4/cos a - 5 = 0

    Multiplying through by cos a, we have;

    4-5cosa = 0=>4 = 5cosa

    4/5 = cosa

    a = cos^{-1}0.8

    =36.88

    Alternatively Cos a = 4/5

    Sina = 3/5; {note Cos a = adjacent / hypothesis and from Pythagoras rule we can derive the value of the opposite side which is;

    5^2 - 4^2 = 25-16 = 9; hence the opposite side is √9 = 3; sin a = opposite / hypothenus = 3/5}

    Substituting the value of Cosa and Sina into the expression below;

    2 cos a + 5 sin a : 2 sin a + 5 cos a

    We have;

    [2*4/5 + 5 * 3/5 ] / [2 * 3/5 + 5 * 4/5]

    [8/5 + 15/5 ] / [6/5 + 20/5]

    [23/5]/[26/5] = 23/5 * 5/26 = 23/26

    =
  2. 30 October, 02:47
    0
    sorry but I don't know the answer for this
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