The coin container on a bus has 10 more nickels than dimes and together the nickels and dimes are worth $3.50. How many nickels and dimes are in the container?

Question

Judah Mcintyre

Mathematics

12 December, 08:22

The coin container on a bus has 10 more nickels than dimes and together the nickels and dimes are worth $3.50. How many nickels and dimes are in the container?

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Answers (2)

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Harper Andersen · Answer 1

(10 + x) $.05 + $.10x = $3.50.

$.50 + $.05x + $.10x = $3.50.

$ (.05 +.10) x = $ (3.50 -.50).

$.15x = $3.00.

x = $3.00/$.15.

x = 20 dimes

So (20 + 10) nickels.

Carlos Paul · Answer 2

So you add 10 nickels and then add the rest of the dimes