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24 November, 18:42

Select the exclusion that fits best with this problem. 3x^2y^2-6xz/6x^2yz

Choices

x = 0

x, y, z = 0

1 + y + y^2, y = 0, 1 - y = 0

a, b = 0, a^2 + ab + b^2 = 0

2x - 1 = 0, 4x^2 + 2x + 1 = 0

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Answers (1)
  1. 24 November, 19:08
    0
    For this case we have the following expression:

    3x ^ 2y ^ 2-6xz / 6x ^ 2yz

    From here, we must exclude all values that make the denominator equal to zero.

    We have then:

    6x ^ 2yz = 0

    Therefore, the results are:

    x = 0

    y = 0

    z = 0

    Answer:

    The exclusion that fits best with this problem is:

    x, y, z = 0
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