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15 November, 20:58

A car can travel 100 miles in the same time that it takes a bus to travel 80 miles. If the rate of the bus is 10 miles per hour slower than the car, find the average rate for each

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  1. 15 November, 21:07
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    Answer: the rate of the car is 50 mph.

    Step-by-step explanation:

    Let x represent the rate of the car. If the rate of the bus is 10 miles per hour slower than the car, it means that the rate of the bus is (x - 10) mph.

    Time = distance/speed

    The car can travel 100 miles in the same time that it takes a bus to travel 80 miles. It means that the time taken by the bus to travel 100 miles is

    100/x

    and the time taken by the car to travel 80 miles is

    80 / (x - 10)

    Since the time is the same, then

    80 / (x - 10) = 100/x

    Cross multiplying, it becomes

    80x = 100 (x - 10)

    80x = 100x - 1000

    100x - 80x = 1000

    20x = 1000

    x = 1000/20

    x = 50 mph
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