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16 October, 16:56

Factor - 8x3 - 2x2 - 12x - 3 by grouping. What is the resulting expression?

(2x2 - 3) (4x + 1)

(-2x2 - 3) (-4x + 1)

(2x2 - 3) (-4x + 1)

(-2x2 - 3) (4x + 1)

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Answers (1)
  1. 16 October, 17:12
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    The answer to your question is the last option (-2x² - 3) (4x + 1)

    Step-by-step explanation:

    Expression - 8x³ - 2x² - 12x - 3

    Order the terms - 8x³ - 12x - 2x² - 3

    Process

    1. - Factor the first two terms and the last two terms

    (-8x³ - 12x²) + (-2x - 3)

    Common factor of the first group - 4x

    Common factor of the second group - 1

    2. - Factor each group

    First group - 4x (2x² + 3)

    Second group - 1 (2x² + 3)

    3. - Factor again by common factor

    -4x (2x² + 3) - 1 (2x² + 3)

    (2x² + 3) (-4x - 1) or - (2x² + 3) (4x + 1) or (-2x² - 3) (4x + 1)
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