What are the zeros of the function f (x) = x2 + 8x + 4, expressed in simplest radical form? x = - 4 ± 2StartRoot 3 EndRoot x = - 4 ± StartRoot 48 EndRoot x = StartFraction negative 8 plus or minus StartRoot 3 EndRoot Over 2 End Fraction x = StartFraction negative 4 plus or minus 4 StartRoot 3 EndRoot Over 2 End Fraction

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Mathematics

16 October, 16:52

What are the zeros of the function f (x) = x2 + 8x + 4, expressed in simplest radical form? x = - 4 ± 2StartRoot 3 EndRoot x = - 4 ± StartRoot 48 EndRoot x = StartFraction negative 8 plus or minus StartRoot 3 EndRoot Over 2 End Fraction x = StartFraction negative 4 plus or minus 4 StartRoot 3 EndRoot Over 2 End Fraction

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Answers (2)

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Nia · Answer 1

x = - 4 ± 2√ (3)

Step-by-step explanation:

Discriminant Δ = √ (8²-4 * (1) * (4)) = √ (48) = √ (4*12) = √ (4) * √ (12) = 2√ (12)

then x = (-8 ± 2√ (12)) : 2 = - 4 ±√ (12) = - 4 ±√ (3*4) = - 4 ± 2√ (3)

Cordell Blackburn · Answer 2

A. on edg

Step-by-step explanation:

Just took the assignment.