Assuming that Switzerland's population is growing exponentially at a continuous rate of 0.19 percent a year and that the 1988 population was 6.9 million, write an expression for the population as a function of time in years. (Let t=0 in 1988.)

P=?

hint: logistic function

Assuming that Switzerland's population is growing exponentially at a continuous rate of 0.19 percent a year and that the 1988 population was 6.9 million, write an expression for the population as a function of time in years. (Let t=0 in 1988.)

P=?

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Mathematics

15 October, 12:44

Assuming that Switzerland's population is growing exponentially at a continuous rate of 0.19 percent a year and that the 1988 population was 6.9 million, write an expression for the population as a function of time in years. (Let t=0 in 1988.)

P=?

hint: logistic function

Assuming that Switzerland's population is growing exponentially at a continuous rate of 0.19 percent a year and that the 1988 population was 6.9 million, write an expression for the population as a function of time in years. (Let t=0 in 1988.)

P=?

+3

Answers (1)

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Aliza · Answer 1

First, the formula would be like this dP / dt = KP.

Secondly, since dP is given which is 6.9. Substitute it from the equation.

P (0) = 6.9 x 10^6

integral 1 divided by pdp which will look like this,

integral 1 / PdP = integral kdt

the answer would be. 0019 or

k=.0019