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31 January, 10:06

The vertices of triangle ABC are A (2,3), B (-1,2), and C (3,1). If ΔDEF ∼ ΔABC and DE = 4AB, what is the length of EF? The answers are √10,√17,4√10,4√17

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  1. 31 January, 10:21
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    EF = 4BC

    BC = sqrt ((3 - (-1) ^2 + (1-2) ^2)

    =" BC = sqrt (4^2 + (-1) ^2) = sqrt17

    =" EF = 4BC = 4 (sqrt 17)
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