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20 April, 21:23

Solve for the exact value (s) of x, 0

2sin2xcosx + sin2x = 0

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  1. 20 April, 21:45
    0
    Sin2x (2cosx+1) = 0

    sin2x=0

    2x=πn, n=0,1,2 ...

    x = (π/2), 3π/2

    2cosx=-1

    cosx=-1/2

    x=arccos (-1/2)

    x=2π/3, 4π/3
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