Ask Question
23 October, 02:33

You roll a number cube three consecutive times. What is the probability that you roll an even number the first two times and a 3 the last time?

+3
Answers (2)
  1. 23 October, 02:45
    0
    1/24.

    Step-by-step explanation:

    Probability (Rolling an even number)

    = 3/6 = 1/2.

    Probability (Rolling a 3) = 1/6.

    Required Probability = 1/2 * 1/2 * 1/6

    = 1/24.

    The probabilities are multiplied because the 3 events are independent.
  2. 23 October, 02:56
    0
    1/24

    Step-by-step explanation:

    A die has 6 faces with numbers 1 through 6. Three faces have even numbers, and 3 faces have odd numbers.

    Each roll of the die can result in 6 different outcomes.

    The total number different outcomes of rolling a die 3 times is 6 * 6 * 6 = 216.

    There are 3 possible even number outcomes on the first roll, and another 3 possible even number outcomes on the second roll. The third roll needs to be a 3, so there is one single desired outcome of the third roll.

    Total number of desired outcomes: 3 * 3 * 1 = 9

    probability (even, even, 3) = 9/216 = 1/24
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “You roll a number cube three consecutive times. What is the probability that you roll an even number the first two times and a 3 the last ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers