Evaluate √x^2 + y^2 when x^2 = 20 and y^2 = 10

5.477

Step-by-step explanation:

Here we have to get the value √ (x²+y²) in this question where the values of x² and y² are given to be 20 and 10 respectively.

Let A = √ (x²+y²) = √ (20+10) {Since the value of x² = 20 and that of y² = 10}

⇒ A = √30 = 5.477

Therefore, the value of √ (x²+y²) is 5.477. (Answer)