The sum of two integers is 49 and their difference is 9. Find the numbers

29 and 20 are such integers.

Step-by-step explanation:

Let one of the two integers = m

let other integer = n

Now, since sum of two integers = 49

⇒ m + n = 49 ... (1)

The difference of two integers = 9

⇒ m - n = 9 ... (2)

Solving both the equations:

Add equations (1) and (2), we get

2 m = 58

or, m = 58 / 2 = 29

or, m = 29

So, one of the integers = m = 29

Now, the other integer is n = 49 - m = 49 - 29 = 20

or, n = 29

Hence, 20 and 29 are such integers.