The perimeter of a rectangle is 32 feet. The length is 6 more than the width. What are the dimensions of the table?

P=2 (L+W)

32=P

32=2 (L+W)

divide by 2 both sides

16=L+W

length is 6 more than width

L=6+W

subsisute 6+W for length in other equation

16=L+W

16=6+W+W

16=6+2W

minsu 6 both sides

10=2W

divide both sides by 2

5=W

sub back

L=6+W

L=6+5

L=11

the length is 11ft

the width is 5ft