If the sin of angle x is 4/5, and the triangle was dilated to be two times as big as the original, what would be the value of the sin of x for the dilated triangle? Hint: Use the slash symbol (/) to represent the fraction bar and enter the fraction with no spaces.

Question

Keenan Butler

Mathematics

13 March, 14:57

If the sin of angle x is 4/5, and the triangle was dilated to be two times as big as the original, what would be the value of the sin of x for the dilated triangle? Hint: Use the slash symbol (/) to represent the fraction bar and enter the fraction with no spaces.

+3

Answers (1)

Know the Answer?

Christine Snow · Answer 1

Given:

Sin x = 4/5

Using the rule of SOH CAH TOA,

we know that,

Sin x = opposite/Hypotenuse

So,

When the triangle is dilated, the opposite side will be dilated to 8 and the Hypotenuse will be dilated to to 10.

which means 4/5 will become 8/10

and hence,

8/10 after simplifying will be 4/5. Thus there is no change.