Walt is wrapping a poster enclosed in a cylindrical tube. The tube has a diameter of 6 centimeters and a length of 50 centimeters. Find the amount of wrapping paper Walt needs. Round to the nearest tenth

Question

Jeramiah Pineda

Mathematics

25 July, 20:16

Walt is wrapping a poster enclosed in a cylindrical tube. The tube has a diameter of 6 centimeters and a length of 50 centimeters. Find the amount of wrapping paper Walt needs. Round to the nearest tenth

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Answers (1)

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Dominique Ritter · Answer 1

A=2pr^2+2prh and r=d/2 so

A = (2pd^2) / 4 + (2pdh) / 2

A = (2pd^2+4pdh) / 4

A = (2pd/4) (d+2h)

A = (pd/2) (d+2h)

A = (6p/2) (6+2*50)

A = (3p) (106)

A=318p cm^2

A≈999.0 cm^2 (to nearest tenth of a square centimeter)