A (t) = (t - k) (t - 3) (t - 6) (t + 3) is a polynomial function of t, where k is a constant. Given that a (2) = 0, what is the absolute value of the product of the zeros of a?
+5
Answers (2)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A (t) = (t - k) (t - 3) (t - 6) (t + 3) is a polynomial function of t, where k is a constant. Given that a (2) = 0, what is the absolute ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Home » Mathematics » A (t) = (t - k) (t - 3) (t - 6) (t + 3) is a polynomial function of t, where k is a constant. Given that a (2) = 0, what is the absolute value of the product of the zeros of a?