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28 November, 05:23

The fourth term of an arithmetic progression is 3. The sum of the fifth and seventh terms is - 10. Find the common difference and the first term. Tq

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  1. 28 November, 05:47
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    4th term = a1 + 3d = 3

    fifth + seventh term = a1 + 4d + a1 + 6d = - 10

    2a1 + 10d = - 10

    a1 + 5d = - 5

    a1 + 3d = 3 Subtract:-

    2d = - 8

    d = - 4

    so a1 - 12 = 3

    a1 = 15

    Answer: - first term = 15 and common difference = - 4
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