Find the probability of exactly 3 successes in 6 trials of a binomial experiment in which the probability of success if 50%. round to the nearest tenth of a percent.

The probability of exactly 3 successes in 6 trials of a binomial experiment in which the probability of success if 50%, is:

31.3% (Rounding to the nearest tenth)

Step-by-step explanation:

With the information provided, P = 0.5, n = 6 and k = 3, we can build the binomial distribution table, this way:

Binomial distribution (n=6, p=0.5)

f (x) F (x)

x Pr[X = x] Pr[X ≤ x]

0 0.0156 0.0156

1 0.0938 0.1094

2 0.2344 0.3438

3 0.3125 0.6563

4 0.2344 0.8906

5 0.0938 0.9844

6 0.0156 1.0000

Under the first column we have the probabilities of success of every value from 0 to 6, and under the second column we have the values for answering the question at least how much probability we have of any number of successes. Our question is exactly 3 successes in 6 trials and we see that value under the first column: 0.3125.

Therefore, the probability of exactly 3 successes in 6 trials of a binomial experiment in which the probability of success if 50%, is:

31.3% (Rounding to the nearest tenth)

Let's recall that the formula for calculating the probability of exact successes is:

P (k out of n) = (n!/k! (n-k) !) * (p∧k * (1-p) ∧ (n-k))

in our case p=0.5, n=6, k=3

(n!/k! (n-k) !) = 20 and (p∧k * (1-p) ∧ (n-k)) = 0.015625

20 * 0.015625 = 0.3125