What is the standard deviation of the following data set rounded to the nearest tenth? 300, 785, 670, 187, 760, 724

Define the data as the array

x = [300, 785, 670, 187, 760, 724].

The size of the array is n = 6

The standard deviation is

s = [Σ (x - μ) ² / (n-1) ]^ (1/2)

The average is

μ = (300+785+670+187+760+724) / 6 = 571

x-μ = [-271, 214, 99, - 384, 189, 153]

(x-μ) ²/5 = [14688, 9159, 1960, 29491, 7144, 4682]

Σ (x-μ) ²/5 = 67125

s - √ (67125) = 259.085

Answer: 259.1 (nearest tenth)