The length of a rectangle is 8 cm more than 3 times its width. The perimeter of the rectangle is 64 cm. Show the equation that would be used to find the dimensions of the rectangle.
Let w = the width. Then 3w = length + 8. So the equation is 64 = 2 (3w - 8) + 2w.
Let w = the width. Then 3w + 8 = length. So the equation is 64 = 2 (3w + 8) + 2w. 64 = 2 (3w + 8) + 2w
Let w = the width. Then 3 (w + 8) = length. So the equation is 64 = 2 (3 (w + 8)) + 2w.
Let w = the width. Then 3w + 8 = length. So the equation is 64 = (3w + 8) w.
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