X^2-4x-5=0 na formula de bhaskara

Solve for x over the real numbers:

x^2 - 4 x - 5 = 0

The left hand side factors into a product with two terms:

(x - 5) (x + 1) = 0

Split into two equations:

x - 5 = 0 or x + 1 = 0

Add 5 to both sides:

x = 5 or x + 1 = 0

Subtract 1 from both sides:

Answer: x = 5 or x = - 1