Out of 56 players on the football team, 24 are on honor roll and 18 have perfect attendence. 7 who are on honor roll also have perfect attendence. If a player is chosen at random, what is the probability that they are on honor roll, if it is known that they also have perfect attendance?

Question

Saige Daugherty

Mathematics

20 October, 02:05

Out of 56 players on the football team, 24 are on honor roll and 18 have perfect attendence. 7 who are on honor roll also have perfect attendence. If a player is chosen at random, what is the probability that they are on honor roll, if it is known that they also have perfect attendance?

+3

Answers (2)

Know the Answer?

Ean Underwood · Answer 1

7/56

Step-by-step explanation:

This is because there are 56 people and seven out of them are on the honor roll and have perfect attendance. You have a seven out of fifty-six chance of choosing them.

Long · Answer 2

There would be a 7/18 chance.

Step-by-step explanation:

Since we are given that we know they have perfect attendance, we limit the sample size to those with perfect attendance (18). Then for the chance, we use the amount who are also on honor role (7). Now we divide the two numbers.

7/18