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21 June, 02:23

A machinist has to manufacture a circular metal disk with area 1060π sq. cms. How close to the exact radius must the machinist control the radius if he is allowed an error tolerance of ±20π sq. cms. in the area of disk?

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  1. 21 June, 02:27
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    The radius of the disk must be close to 33cm

    Step-by-step explanation:

    Formula for calculating the area of a circular metal disk is Πr² since area of a circle is Πr². If the area of the disk is 1060π sq. cms, to get the radius of the disc, we will use the formula;

    A = Πr² where;

    A is the area of the disc

    r is the radius of the disc

    Given A = 1060π sq. cms

    1060Π = Πr²

    1060 = r²

    r = √1060

    r = 32.56cm approximately

    If he is allowed a tolerance of ±20Πsq. cms in area, this means that we can use 1060±20Πsq. cms as the area which is equivalent to either 1080sq. cms or 1040sq. cms

    If A = 1080sq. cms

    r = √1080 = 32.86cm

    If A = 1040sq. cms

    r = √1040 = 32.25cm

    If the values of the radius are compared, the radius of the metal disk must be close to 33cm approximately which are within the tolerance limit of the area.
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