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27 March, 23:46

By how much does a 3 - 2a exceed a 2 + a - 6?

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  1. 27 March, 23:54
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    A^3 - 2a - (a^2 + a - 6) =

    a^3 - 2a - a^2 - a + 6 =

    a^3 - a^2 - 3a + 6 <==
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