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3 July, 15:53

Write the standard equation for a circle with center (-6, - 8), that passes through (0, 0)

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  1. 3 July, 15:56
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    Standard equation: (x-h) ^2 + (y-k) ^2 = r^2

    Here, (0-[-6]) ^2 + (0-[-8]) ^2 = r^2

    Find r: 36 + 64 = 100, so r = 10

    Then the desired equation is (x+6) ^2 + (y+8) ^2 = 10^2
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