Two captains need to be chosen from a fifteen person team. if the captain positions are identical, how many different ways can the two captains be selected?

In 105 different ways

Step-by-step explanation:

To solve this problem we will use combinations without repetitions.

C (n k) = V (n k) / k!

In this case n = 15 and k = 2

C (15 2) = V (15 2) / 2! = 15 · 14 / 2 = 15 · 7 = 105

The two captains can be selected in the 105 different ways (combinations).

God with you!