Ask Question
5 March, 02:12

Determine the center and radius of the following circle equation:

x² + y² - 10x + 20y + 89 = 0

+4
Answers (1)
  1. 5 March, 02:17
    0
    The center is (-5, - 10) and the radius = 6.

    Step-by-step explanation:

    Convert the equation to standard form by completing the square;

    x^2 + y^2 - 10x + 20y + 89 = 0

    x^2 + y^2 - 10x + 20y = - 89

    x^2 - 10x + y^2 + 20y = - 89 Completing the square:

    (x + 5) ^2 - 25 + (y + 10) ^2 - 100 = - 89

    (x + 5) ^2 + (y + 10) ^2 = - 89 + 125

    (x + 5) ^2 + (y + 10) ^2 = 36

    Comparing this to the standard form:

    (x - h) ^2 + (y - k) ^2 = r^2

    - we see that the center is (-5, - 10) and the radius = 6.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Determine the center and radius of the following circle equation: x² + y² - 10x + 20y + 89 = 0 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers