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30 July, 13:54

If H (x) = 4x^2-16 was shifted 7 units to the right and 3 down, what would the new equation be? a. h (x) = 4 (x+9) ^2-17 b. h (x) = 4 (x-9) ^2-17 c. h (x) = 4 (x-7) ^2 - 19 d. h (x) = 4 (x+7) ^2 + 19

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  1. 30 July, 14:21
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    In general,

    right shift h is given by

    f (x-h) - >g (x)

    up shift is given by

    f (x) + k->g (x)

    So for h=7, and k=-3, we have

    H (x-7) - 3

    =4 (x-7) ²-16-3

    =4 (x-7) ²-19
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