Ask Question
30 October, 14:40

The owner of a candy store wants to mix some peanuts worth $3 per pound, some cashews worth $10 per pound, and some Brazil nuts worth $9 per pound to get 50 pounds of a mixture that will sell for $6.80 per pound. She uses 10 fewer pounds of cashews than peanuts. How many pounds of each did she use?

+5
Answers (1)
  1. 30 October, 15:01
    0
    Let

    x = pounds of peanuts

    y = pounds of cashews

    z = pounds of Brazil nuts.

    The total pounds is 50, therefore

    x + y + z = 50 (1)

    The total cost is $6.60 per pound for 50 pounds of mixture.

    The total is equal to the sum of the costs of the different nuts.

    Because the cost for peanuts, cashews, and Brazil nuts are $3, $10, and $9 respectively, therefore

    3x + 10y + 9z = 50*6.8

    3x + 10y + 9z = 340 (2)

    There are 10 fewer pounds of cashews than peanuts, therefore

    x = y + 10 (3)

    Substitute (3) into (1) and (2).

    y + 10 + y + z = 50

    2y + z = 40 (4)

    3 (y + 10) + 10y + 9z = 340

    13y + 9z = 310 (5)

    From (4),

    z = 40 - 2y (6)

    Substitute (6) into (5).

    13y + 9 (40 - 2y) = 310

    -5y = - 50

    y = 10

    z = 40 - 2y = 40 - 20 = 20

    x = y + 10 = 20

    Answer:

    Peanuts: 20 pounds

    Cashews: 10 pounds

    Brazil nuts: 20 pounds
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The owner of a candy store wants to mix some peanuts worth $3 per pound, some cashews worth $10 per pound, and some Brazil nuts worth $9 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers