If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation hequals=minus-16t squaredt2plus+vtplus+ s, where h is in feet. if the object is propelled from a height of 88 feet with an initial velocity of 6464 feet per second, its height h is given by the equation hequals=minus-16t squaredt2plus+6464tplus+88. after how many seconds is the height 3636 feet?
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