Ask Question
21 January, 10:57

If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation hequals=minus-16t squaredt2plus+vtplus+ s, where h is in feet. if the object is propelled from a height of 88 feet with an initial velocity of 6464 feet per second, its height h is given by the equation hequals=minus-16t squaredt2plus+6464tplus+88. after how many seconds is the height 3636 feet?

+3
Answers (1)
  1. 21 January, 11:26
    0
    Im sorry i have no idea i think it would be half the time of 6464 ft per second
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers