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15 June, 23:32

Subtract these polynomials. (3x^2+6x+7) - (6x^2-5x-7)

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  1. 15 June, 23:39
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    3x²-11x-14=0

    Step-by-step explanation:

    Given equation is : (3x²+6x+7) - (6x²-5x-7)

    Putting the equation equals to zero making it in the form of polynomial equation (3x²+6x+7) - (6x²-5x-7) = 0

    Opening the bracket of the equation, the negative sign outside the bracket changes the sign of the values after opening the bracket.

    3x²+6x+7-6x²+5x+7=0

    Solving this by subtracting the values of same type i. e subtracting the component of x having the same power.

    3x²-6x²+6x+5x+7+7=0

    -3x²+11x+14=0 OR 3x²-11x-14=0

    So, on subtracting the above equation the quadratic equation is obtained 3x²-11x-14=0
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