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16 September, 06:56

In rhombus fmkw mk=12 fk = 16 m

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  1. 16 September, 07:06
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    If it is area your looking for.

    Area = product of diagonal lengths divided by 2

    Area = 12 * 16 / 2

    =192/2 = 96.

    IF it is the side length of the rhombus:

    apply Pythagoras theorem since the diagonals always meet at 90°.

    L = √ (12² + 16²)

    L = √400 = 20
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