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23 February, 23:43

Manny rolls a number cube labeled 1 through 6 and spins a spinner with

four equal sections labeled 1, 2, 3, and 4. If both numbers are odd, he wins.

Otherwise, Gabriel wins. Usa a list to find the sample space. Then find the

probability that Gabriel wins.

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  1. 23 February, 23:45
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    The winning probability of Gabriel would be = 3/4.

    Step-by-step explanation:

    Given,

    The sides of number cube = 6 {1, 2, 3, 4, 5, 6}

    The sides of a spinner = 4 {1, 2, 3, 4}

    If both the gadgets are played together, the sample space (S) size would be:

    6 x 4 = 24

    Hence,

    S = { (1, 1), (1, 2), (1, 3), (1, 4)

    (2, 1), (2, 2), (2, 3), (2, 4)

    (3, 1), (3, 2), (3, 3), (3, 4)

    (4, 1), (4, 2), (4, 3), (4, 4)

    (5, 1), (5, 2), (5, 3), (5, 4)

    (6, 1), (6, 2), (6, 3), (6, 4) }

    Manny wins if both the number are odd.

    So, the winning chances of many are (1, 1), (1, 3), (3, 1), (3, 3) (5, 1) (5, 3) = 6

    Therefore, the winning chances of Gabriel would be = 24 - 6 = 18

    Therefore, the winning probability of Gabriel would be = 18/24 = 3/4.
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