Jason and Sheldon are neighbors who work for the same accounting firm. They leave the office at the same time. After t seconds, Jason's distance from the office in meters is given as 4 more than 3 times t, while Sheldon's distance from the office is 6 more than 2 times t.

The function that represents the total distance d (t) that Jason and Sheldon cover together in t seconds is given by d (t) = t - 2 t + 2 5t - 10 5t + 10. In 7 seconds, Jason and Sheldon together cover a distance of 5 9 25 45 meters.

Question

Jefferson Santana

Mathematics

3 March, 21:25

Jason and Sheldon are neighbors who work for the same accounting firm. They leave the office at the same time. After t seconds, Jason's distance from the office in meters is given as 4 more than 3 times t, while Sheldon's distance from the office is 6 more than 2 times t.

The function that represents the total distance d (t) that Jason and Sheldon cover together in t seconds is given by d (t) = t - 2 t + 2 5t - 10 5t + 10. In 7 seconds, Jason and Sheldon together cover a distance of 5 9 25 45 meters.

+5

Answers (1)

Know the Answer?

Alexander Simon · Answer 1

Jason's distance from office: 4 + 3t

Sheldon's distance from office: 6 + 2t

Total distance covered together, d (t) = 4 + 3t + 6 + 2t = 10 + 5t

Answer 1: d (t) = 5t + 10

In 7 seconds: d (7) = 5 (7) + 10 = 35 + 10 = 45

Answer 2: 45 meters