If x = - 2 and x^2+y^2+3xy = -5, then find y

y = 3

Step-by-step explanation:

Given:

x²+y²+3xy = -5 and x = - 2

Substituting x=-2 into the equation:

(-2) ² + y² + 3y (-2) = - 5

4 + y² - 6y = - 5

y² - 6y + 4 + 5 = 0

y² - 6y + 9 = 0 (solve by factorization)

(y-3) (y-3) = 0

y = 3